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1. Given the following code, which procedure call would cause the "Pointer corrupted!" message to be output
provided that the PL/I compile time option CHECK(STORAGE) has been specified?
DCLX FIXED BIN(31) BASED (P);
DCL Y CHAR (5) BASED (P);
DCL P POINTER;
SUB: PROCEDURE (P);
DCL P POINTER;
if CHECKSTG(P) THEN PUT ('Pointer 0k!');
ELSE PUT ('Pointer corrupted!');
END;
A) P = ALLOCATE (100);
Y = 'ABCDE';
CALL SUB (ADDR(X));
B) ALLOCATEY;
Y = 'ABCDE';
CALL SUB (P);
C) ALLOCATEY;
Y = 'ABCDE';
CALL SUB (ADDR(X));
D) ALLOCATEX;
Y = 'ABCD';
CALL SUB (P);
2. PL/I programs which have been written under Intel architecture are now to be recompiled and run on the
mainframe. What will happen to the programs during compilation and execution?
A) They can be recompiled unchanged and will run correctly.
B) They will not run correctly because the byte order on mainframe is bigendian.
C) They will not compile correctly on mainframe because ASCII has no NOT sign.
D) They may have to be changed before they run correctly on the mainframe.
3. What characterizes the hierarchical data model with respect to data access?
A) Data access supports tables.
B) Data access can only be sequential.
C) Data access can only be via an index.
D) Data access supports parent-child relationships.
4. WIDECHAR can be converted to CHAR. Which rule has to be observed?
A) By conversion of WIDECHAR to CHAR the left byte is omitted.
B) Each WIDECHAR value has to be less than '0080'WX, otherwise CONVERSION is raised.
C) All WIDECHAR values can be converted to CHAP using the appropriate builtin function.
D) Each WIDECHAR value has to be less than or equal to '00FF'WX, otherwise CONVERSIONis raised.
5. Requirement:
If the value of the numeric variable I is 1 it needs to be changed to 2 and vice versa. In all other cases it
must remain unchanged. Which of the following solutions meets the requirement and does not require
essential structural modifications when the requirement is changed to the following: If the value of the
numeric variable I is 512 it needs to be changed to 731 and if the value is 814 it needs to be changed to 5.
In all other cases it must be set to 111.
A) lF I = 1 ! 1 = 2
THEN I = 3 - I;
B) SELECT (I);
WHEN(1) I = 2;
WHEN(2) I = 1;
OTHER;
END;
C) IF I = 1 THEN I = 2;
IF I = 2 THEN I = 1;
D) DCL ONETWO(2) BIN FIXED(15) INIT(2,1);
IF I = 1! I = 2
THEN I = ONETWO(I);
Solutions:
| Question # 1 Answer: D | Question # 2 Answer: D | Question # 3 Answer: D | Question # 4 Answer: B | Question # 5 Answer: B |
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